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coldgirl [10]
3 years ago
10

Austin checks the temperature at 10:00 p.m. He notices if the temperature

Mathematics
1 answer:
Alecsey [184]3 years ago
4 0

Answer:

A. t - 5 < 26°

Step-by-step explanation:

Record low temperature for that date = 26°

Temperature at 10:00 PM = t

A fall in temperature by 5° = t - 5

Thus, this is said would mean the record low temperature would be breaking at this point, meaning the new temperature low recorded will be less than 26°.

In mathematical expression, this is expressed as;

t - 5 < 26°

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Solve x^2-6x+25 = 0 by completing the square.
Oksana_A [137]

First, subtract both sides by 25:

x^2 - 6x = -25

Because we're completing the square, we subtract both sides by 9:

x^2 - 6x - 9 = -34

(x - 3) = 5.831 (about)

x = 8.831

3 0
3 years ago
What is the population variance for 138, 151, 169, 142, 176, 155, 132, 177
ruslelena [56]

Answer:

265.50000

Step-by-step explanation:

3 0
2 years ago
We have a right triangle that has am 8 meter and 21 meter leg .Find the hypotenuse
Serjik [45]

Answer:

hypotenuse is 22.47 m

Step-by-step explanation:

The length of both legs of a right angle triangle are 8m and 21 m

We need to find the hypotenuse

To find hypotenuse we use Pythagorean theorem

Hypotenuse is AC  and other two legs are AB  and BC

AC^2 = AB^2 + BC^2

Hypotenuse ^2 = 8^2 + 21^2

hypotenuse = \sqrt{8^2 + 21^2}

= \sqrt{64 + 441}

= \sqrt{505}

= 22.47

So the length of the hypotenuse is 22.47 m

4 0
3 years ago
Blue cassests hold 45 min. Of music
zhannawk [14.2K]
Let the number of Blue casset be b and that of green be g.
Thus the total number of cassets will be:
b+g=16
hence
g=16-b.......i

The total amount was:
45b+55g=830..ii
plugging i in ii we get:
45b+55(16-b)=830
45b+880-55b=830
simplifying 
45b-55b=830-880
-10b=-50
thus
b=5
hence
g=16-5=11
number of blue cassets was 5 and that of green was 11 
5 0
3 years ago
Find f.<br><br> A) 7.4<br><br> B) 8.2<br><br> C) 10.5<br><br> D) 11.1
tatyana61 [14]
F=72

g=6

------------

\cos { \left( F \right)  } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }

Therefore:

\cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }

\\ \\ 12e\cdot \cos { \left( 72 \right)  } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right)  } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 }  } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right)  }  \right) +36 }

But what is e?

E=76

G=32

g=6

And:

\frac { e }{ \sin { \left( E \right)  }  } =\frac { g }{ \sin { \left( G \right)  }  }

Which means that:

\frac { e }{ \sin { \left( 76 \right)  }  } =\frac { 6 }{ \sin { \left( 32 \right)  }  } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  }

If you take this value into account, you will discover that f is...

f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } \left( \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } -12\cos { \left( 72 \right)  }  \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)

So I would have to say that the answer is approximately (c).
6 0
3 years ago
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