All categories

2 years ago

Please I need help please

Mathematics

2 answers:

Bogdan [553]2 years ago

6 0

B. your first number needs to be between 1-10

bezimeni [28]2 years ago

3 0

Answer:

the answer is 41 billion

Step-by-step explanation:

You might be interested in

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago

If f(x) = 2x + 5x and g(x) = 3x - 5, find (f+ g)(x).

Papessa [141]

Answer:

D. 10x - 5

General Formulas and Concepts:

Algebra I

Terms/Coefficients/Degrees

Step-by-step explanation:

Step 1: Define

f(x) = 2x + 5x

g(x) = 3x - 5

(f + g)(x) is f(x) + g(x)

Step 2: Simplify

f(x) = 7x

g(x) = 3x - 5

Step 3: Find

Substitute: (f + g)(x) = 7x + (3x - 5)
Combine like terms: (f + g)(x) = 10x - 5

7 0

3 years ago

Fernando factored 45y^6 as (9y^3)(5y^3).

marishachu [46]

Answer:

They both factored it correctly

Step-by-step explanation:

To find the one that was factored correctly, we expand the two of them and compare with $45y^6$ .

Fernando

$(9y^3)(5y^3)$

= $9 * 5 * y^3 * y^3$

= $45y^6$

Salma

$(3y)(15y^5)$

= $3 * 15 * y * y^5$

= $45y^6$

As we can see, they both factored it correctly.

4 0

2 years ago

Which certificate does Jenny require?

Airida [17]

Can you give some more details please thank you

7 0

3 years ago

What are the solutions to the following equation? x^2+8x+15=0

zubka84 [21]

Answer: It can be either one.

x=−3

x=−5

8 0

2 years ago