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harkovskaia [24]
2 years ago
11

Please I need help please

Mathematics
2 answers:
Bogdan [553]2 years ago
6 0
B. your first number needs to be between 1-10
bezimeni [28]2 years ago
3 0

Answer:

the answer is 41 billion

Step-by-step explanation:

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At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

                 y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we |  | get \\

z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

derivative first equation w . r. to t we get

2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

     = \frac{1100}{85.44}\\  = 12.87km/h

8 0
2 years ago
If f(x) = 2x + 5x and g(x) = 3x - 5, find (f+ g)(x).
Papessa [141]

Answer:

D. 10x - 5

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients/Degrees

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 2x + 5x

g(x) = 3x - 5

(f + g)(x) is f(x) + g(x)

<u>Step 2: Simplify</u>

f(x) = 7x

g(x) = 3x - 5

<u>Step 3: Find</u>

  1. Substitute:                     (f + g)(x) = 7x + (3x - 5)
  2. Combine like terms:     (f + g)(x) = 10x - 5
7 0
3 years ago
Fernando factored 45y^6 as (9y^3)(5y^3).
marishachu [46]

Answer:

They both factored it correctly

Step-by-step explanation:

To find the one that was factored correctly, we expand the two of them and compare with 45y^6.

Fernando

(9y^3)(5y^3)

= 9 * 5 * y^3 * y^3

= 45y^6

Salma

(3y)(15y^5)

= 3 * 15 * y * y^5

= 45y^6

As we can see, they both factored it correctly.

4 0
2 years ago
Which certificate does Jenny require?
Airida [17]
Can you give some more details please thank you
7 0
3 years ago
What are the solutions to the following equation? x^2+8x+15=0
zubka84 [21]

Answer: It can be either one.

x=−3

or

x=−5

8 0
2 years ago
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