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4 years ago

What is the four x to the power of two subtract twenty x

1 answer:

ioda4 years ago

3 0

You can start by pulling out a gcf of 4x. that will leave you with 4x(x-5). you should then set your new equation equal to 0 and solve.

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Please help me with this problem!!! No Links!

DerKrebs [107]

The answer is 17! Hope it helps :)

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3 years ago

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Samara has an assignment to conduct a survey. She wants to find out what students like to do after school. She asks the first 10

horrorfan [7]

The answer is
C) Samara’s sample is random because she asks the first 10 people she sees.

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3 years ago

Determine the volume of the figure. Use 3.14 for π. Round your answer to the nearest tenth. Show all of your work.

Ostrovityanka [42]

Answer:

1985 cubic units (written as un. with the cubed exponent)

Step-by-step explanation:

First, you find the volume of the cylinder

Here's the formula:

$V=\pi r^{2}h\\V=volume\\r=radius\\h=height$

Now, you plug in and solve.

$V=(3.14)(7.2^{2})(7.4)\\V=(3.14)(51.84)(7.4)\\V=(162.7776)(7.4)\\V=1204.55424\\rounded:\\V=1204.6$

Then, you find the volume of the dome.

Here's the formula:

$volume/of/a/sphere=\frac{4}{3}\pi r^{3}\\volume/of/a/dome:\\V=\frac{2}{3}\pi r^{3} \\V=volume\\r=radius$

Now, you just plug in and solve.

$V=(\frac{2}{3})(\pi)(r^{3})\\V=(\frac{2}{3})(3.14)(7.2^{3})\\V=(\frac{2}{3})(3.14)(373.248)\\V=(2.093)(373.248)\\V=781.208064\\rounded:\\V=781.2$

Finally, you add them together, and there's your answer!

$1204.6+781.2=1985.8$

Hope this helped!

brainliest?

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3 years ago

An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the

julia-pushkina [17]

Answer:

The rate of decrease is: $43.2mm^3/min$

Step-by-step explanation:

Given

$l = 18mm$

$\frac{dl}{dt} = -0.8mm/min$ ---- We used minus because the rate is decreasing

Required

Rate of decrease when: $l = 18mm$

The volume of the cube is:

$V = l^3$

Differentiate

$\frac{dV}{dl} = 3l^2$

Make dV the subject

$dV = 3l^2 \cdot dl$

Divide both sides by dt

$\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}$

Given that: $l = 18mm$ and $\frac{dl}{dt} = -0.8mm/min$

$\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)$

$\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min$

$\frac{dV}{dt} = -43.2mm^3/min$

Hence, the rate of decrease is: 43.2mm^3/min

8 0

3 years ago

In kite PQRS, m∠TQP=63°. Identify m∠QPT.

mario62 [17]

Assuming m<PTQ is a right angle (measuring 90°) and angle TQP is already marked as 63° while knowing there are 180° in a triangle, you would take 180°- 63°- 90°= 27

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3 years ago

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