Please help! Question above (+10 points)

Mathematics

1 answer:

cricket20 [7]3 years ago

3 0

There are three answers and they are: choice 2, choice 3, choice 5

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Further Explanation:

Choice 1 is false because the intersection of the altitudes of a triangle leads to the orthocenter.

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Choice 2 is true because the three medians of any triangle always intersect at the centroid. A median is a line that goes from one vertex to the midpoint of the opposite side. In this case, we go from point E to the midpoint of side CD. The midpoint of CD is found by bisecting segment CD (see choice 5)

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Choice 3 is true. This is effectively the same as choice 5 below. The "perpendicular" aspect does not matter.

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Choice 4 is false. Following the steps mentioned here will create an altitude line (see choice 1)

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Choice 5 is true. To bisect something is to cut it in half. Let's say that point F is the midpoint of line segment CD. This means that line segment EF is one of the three medians of triangle CDE.

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edit update: I changed choice 3 from false to true

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help!!!!!!!!!!!!!!!!!!!!!!!!!

Simora [160]

9²+15²=a²

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3 0

3 years ago

Two hikers come to a ravine and want to know how wide it is. They set up two similar triangles as shown in the diagram. How far

dolphi86 [110]

Answer:

d = 80 ft

Step-by-step explanation:

Start with angle BCA, tan(BCA) = 30/15 so BCA = 63.43 degrees.

BCA = ECD since they are opposite angles.

tan ECD = d/40

40 tan(63.4degrees) = d

d = 80 ft

Alternatively, you can use similar triangles since the angles are the same, BCA = ECD, CED = CAB, and CBA = EDC. In that case use proportions to get 30/15 = d/40 so 2 = d/40 and d = 80.

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3 years ago

Find the radius of convergence and the internval of convergence:

o-na [289]

You can use the root test here. The series will converge if

$L=\displaystyle\lim_{n\to\infty}\sqrt[n]{\frac{(4-x)^n}{4^n+9^n}}$

You have

$L=\displaystyle\lim_{n\to\infty}\sqrt[n]{\frac{(4-x)^n}{4^n+9^n}}=|4-x|\lim_{n\to\infty}\frac1{\sqrt[n]{4^n+9^n}}$

Notice that

$\dfrac1{\sqrt[n]{4^n+9^n}}=\dfrac1{\sqrt[n]{9^n}\sqrt[n]{1+\left(\frac49\right)^n}}=\dfrac1{9\sqrt[n]{1+\left(\frac49\right)^n}}$

so as $n\to\infty$ , you have $\left(\dfrac49\right)^n\to0$ , which means you end up with

$L=\dfrac{|4x-1|}9$

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$|4x-1|$