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soldier1979 [14.2K]
3 years ago
7

Samara has an assignment to conduct a survey. She wants to find out what students like to do after school. She asks the first 10

people she sees in her Book Club what they like to do after school. Which statement correctly explains whether Samara's sample is a random sample?
Question 6 options:

A) Samara’s sample is not random because she only asks 10 people.


B) Samara's sample is random because she asks each person the same question.


C) Samara’s sample is random because she asks the first 10 people she sees.


D) Samara’s sample is not random because she only asks people in a book club
Mathematics
1 answer:
horrorfan [7]3 years ago
7 0
The answer is
<span>C) Samara’s sample is random because she asks the first 10 people she sees.
</span>
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Answer:

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Step-by-step explanation:

We are given the following in the question:

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Formula:

Potential energy  =

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You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the
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Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that n = 2809, \pi = \frac{1634}{2809} = 0.5817

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

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Because i can't see the graph

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