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Bad White [126]
3 years ago
13

How do I find X? This is a quadrilateral inside of a circle.

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

circle it?

Step-by-step explanation:

°

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Given: is an angle bisector of ∠JMK<br><br><br>Prove: m
astraxan [27]

Answer:

An angle bisector is a line passing through the vertex of the angle that cuts the angle into two equal smaller angles.

Given: MN is angle bisector,

then  

\angle JMN \cong \angle NMK            .......  [1]

Congruent angles are  two or more angles that have the same measure.

then;

by definition of congruent angles

[1]⇒ m\angle JMN = m\angle NMK                ......[2]

By the  Angle addition postulates states that if M is in the interior of ∠JMK then,

m\angle JMN+m\angle NMK =m\angle JMK            ......[3]

Now, by substitution property ; substitute the equation [2] in [3] we get;

m\angle JMN+m\angle JMN =m\angle JMK                 ......[4]

Like terms terms whose variables  are the same

Combine like terms in equation [4] we get

2 \cdot m\angle JMN=m\angle JMK                      ......[5]

Division property of equality states that you divide the same number to both sides of an equation.

Divide by 2 to both sides in equation [5] , we get

m\angle JMN= \frac{1}{2} m\angle JMK    


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UkoKoshka [18]

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2 years ago
Find the measure of the missing angles.
Karolina [17]

Answer:

angles b and c should be 153° each.

Step-by-step explanation:

We know the smaller angle is 27°. The other small angle, vertical to the 27° angle is also 27° because they are vertical angles. Along the lines, two angles should form 180°. So 180-27=153°. All together the angles should be 360°. Check your answer by doing 153+153+27+27=360. therefore the missing angles are both 153°

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3 years ago
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0Step-by-step explanation888    :8

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3 years ago
If f(x)=ln x and g(x)=e^x+1 find f(g(2))-g(f(e)) please help!!
Readme [11.4K]

Answer:

<h3>ln (e^2 + 1) - (e+ 1)</h3>

Step-by-step explanation:

Given f(x) = ln and g(x) = e^x + 1 to get  f(g(2))-g(f(e)), we need to first find the composite function f(g(x)) and g(f(x)).

For f(g(x));

f(g(x)) = f(e^x + 1)

substitute x for e^x + 1 in f(x)

f(g(x)) = ln (e^x + 1)

f(g(2)) = ln (e^2 + 1)

For g(f(x));

g(f(x)) = g(ln x)

substitute x for ln x in g(x)

g(f(x)) =  e^lnx + 1

g(f(x)) = x+1

g(f(e)) = e+1

f(g(2))-g(f(e)) = ln (e^2 + 1) - (e+ 1)

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3 years ago
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