What is 3.45 written as a percentage?

Johnny sold crafts at a show. His prices included .07 sales tax. Johnny grossed $1236.00. What was johnny's taxable amount?

Vadim26 [7]

The taxable amount was $80.86

Step-by-step explanation:

Given,

Sales tax = .07

Total grossed = $1236.00

Let,

x be the price before sales tax, therefore,

Amount of sales tax = 0.07x

Price before sales tax + Sales tax = Total amount grossed

x+0.07x = 1236

1.07x=1236

Dividing both sides by 1.07

$\frac{1.07x}{1.07}=\frac{1236}{1.07}\\x=1155.14$

Taxable amount = Total amount grossed - Price before tax

Taxable amount = 1236 - 1155.14 = $80.86

The taxable amount was $80.86

Keywords: subtraction, addition

Learn more about subtraction at:

#LearnwithBrainly

5 0

3 years ago

( 1/4) ꓥ -3 = A= -64 B= -1/64 C= 1/64 D= 64

Anna11 [10]

Answer:

C-1/64

Step-by-step explanation:

(1/4)(1/4)(1/4)=1/64

Mark the brainliest

5 0

3 years ago

Simplify the trigonometric expression. sin4(α) − cos4(α) + cos2(α)

natulia [17]

Answer:

sin²(α)

Step-by-step explanation:

sin⁴(α) − cos⁴(α) + cos²(α)

sin⁴(α) − cos²(α) (cos²(α) − 1)

sin⁴(α) − cos²(α) (-sin²(α))

sin⁴(α) + sin²(α) cos²(α)

sin²(α) (sin²(α) + cos²(α))

sin²(α) (1)

sin²(α)

5 0

3 years ago

16.Speedy Rentals charges $300 per month to rent a car plus an initial deposit of $500. Thrifty Rentals charges $200 per month t

pentagon [3]

Answer:

A: Speedy Rentals is $100 cheaper if you only rent a car for 4 months

B: If you rented a car for 5 months then both places woulb be the same amount

Step-by-step explanation:

8 0

3 years ago

Rothamsted Experimental Station (England) has studied wheat production since 1852. Each year many small plots of equal size but

podryga [215]

Answer:

(a) 0.653

(b) 0.0198

(c) Yes, after testing we conclude that the population variance of annual wheat production for the first plot is larger than that for the second plot.

Step-by-step explanation:

(a) We are give the sample of one year annual production of wheat (in pounds) ;

4.46, 4.21, 4.40, 4.81, 2.81, 2.90, 4.93, 3.54, 4.16, 4.48, 3.26, 4.74, 4.97, 4.02, 4.91, 2.59

For calculating sample variance, firstly we will calculate mean of the above data;

Mean of above data, $X_1bar$ = Sum of all values ÷ n (no. of values)

= $\frac{4.46 + 4.21+4.40+.......+4.91+2.59}{16}$ = 4.074

Sample Variance, $s_1^{2}$ = $\frac{\sum (X-X_1bar)^{2} }{n-1}$ = $\frac{(4.46-4.074)^{2}+(4.21-4.074)^{2}+.........+(4.91-4.074)^{2}+(2.59-4.074)^{2} }{16-1}$ = 0.653

(b) Another sample for annual wheat production (in pounds);

3.89, 3.81, 3.95, 4.07, 4.01, 3.73, 4.02, 3.78, 3.72, 3.96, 3.62, 3.76, 4.02, 3.73, 3.94, 4.03

Mean of above data, $X_2bar$ = Sum of all values ÷ n (no. of values)

= $\frac{3.89+3.81+3.95.......+3.94+4.03}{16}$ = 3.88

Sample Variance, $s_2^{2}$ = $\frac{\sum (X-X_2bar)^{2} }{n-1}$ = $\frac{(3.89-3.88)^{2}+(3.81-3.88)^{2}+.........+(3.94-3.88)^{2}+(4.03-3.88)^{2} }{16-1}$ = 0.0198

(c) Now, we have to test the claim that population variance of annual wheat production for the first plot is larger than that for the second plot i.e.;

Null Hypothesis, $H_0$ : $\sigma_1^{2} = \sigma_2^{2}$ or $H_0$ : $\frac{\sigma_1^{2} }{\sigma_2^{2} } = 1$

Alternate Hypothesis, $H_0$ : $\sigma_1^{2} > \sigma_2^{2}$ or $H_0$ : $\frac{\sigma_1^{2} }{\sigma_2^{2} } > 1$

The test statistics used here is;

$\frac{s_1^{2} }{s_2^{2} }* \frac{\sigma_1^{2} }{\sigma_2^{2}}$ ~ $F_n__1-1_,n_2-1$ where, $n_1 = 16$ and $n_2 =16$

Test Statistics = $\frac{0.653 }{ 0.0198}* 1$ ~ $F_1_5_,_1_5$

= 32.98

Since, we are not provided with any significance level so we assume it to be 5% and at this level, the F table gives critical value of 2.4282.

Since our test statistics is higher than the critical value and it falls in the rejection region so we have sufficient evidence to reject null hypothesis and conclude that the population variance of annual wheat production for the first plot is larger than that for the second plot.

8 0

3 years ago