Group points {(0,1),(0,5)(2,6),(3,3)}is not a function, but group points {(1,4)(2,7)(3,1)(5,7)} is a function. What do you notic
Tasya [4]
<h2>Any value in the domain of the function should have a unique value in codomain.</h2>
Step-by-step explanation:
In the first set of points 

,
value
maps to two distinct values
in the codomain.
This violates the property of functions.
The first set of points does not form a function.
In the second set of points 

,
Every value in domain corresponds to unique value in domain.
There is no violation in the property of functions.
The second set of points does form a function.
Answer:
I dont get the question
Step-by-step explanation:
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I think it's D. 7 times out of 34 times
The surface area of a sphere is 4r^2pi, so dividing 100 by 4pi gives a result of 25/pi. Taking the square root and rationalizing the denominator, we have 5sqrt(pi)/pi as the radius of the sphere.