Complete question :
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.
Answer:
0.10868
Step-by-step explanation:
Given that :
Mean (m) = 3.02
Standard deviation (s) = 0.29
Sample size (n) = 20
Probability of 3.10 GPA or higher
P(x ≥ 3.10)
Applying the relation to obtain the standardized score (Z) :
Z = (x - m) / s /√n
Z = (3.10 - 3.02) / 0.29 / √20
Z = 0.08 / 0.0648459
Z = 1.2336940
p(Z ≥ 1.2336) = 0.10868 ( Z probability calculator)
Answer:
bndflvb
Step-by-step explanation:
If the center is in point P(a,b) and has a radius r then circle equation is:
(x-a)²+(y-b)²=r².
In your task we've got P(0,0) so the circle equation is x²+y²=r².
We have to find r. Radius start at (0,0) and end at (-4,-6) therefore
r=√((-4)²+(-6)²) and
r²=(-4)²+(-6)²=16+36=52.
So answer is x²+y²=52.
Answer:
Equations weren't provided in the question but my answer is 3T=108
Step-by-step explanation:
t is oranges sold on Thursday.
f is oranges sold on Friday
If she sold the amount she sold on Friday is equal to 2x the amount on Thursday: 2t=f. But the total of 108 is both days added together. So she sold 2t on friday and 1t or ton thursday than you add it up like so: 2t+t=108 becasue 108 is the total. But 2t+t=3t so you get the final equation as 3t=108
The right answer is
Rolls 2 4 6 8
Value $4 $8 $12 $16
