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3 years ago

draw and mark a figure in which M is the midpoint of ST, SP=PT, and T is the midpoint of PQ. i don’t know how to do it!

Mathematics

2 answers:

Akimi4 [234]3 years ago

7 0

Answer:

Draw a segment ST.

Draw Perpendicular bisector of segment ST.The Point where the perpendicular bisector cuts the segment ST,is point M.

From T and S, mark arcs at equal distances on both side of Line segment.Name the Point of Intersection of any of these arcs as point P.

Produce PT on that side where point T lies.

With the help of compass measure the length of segment TP and mark arc on the produced segment PT .Name it as point Q.Join TQ and SQ.

Virty [35]3 years ago

6 0

See attachment

the midpoint is the point that is in the middle of the segment

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Answer:

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Step-by-step explanation:

Let $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ , we proceed to prove the trigonometric expression by trigonometric identity:

1) $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ Given

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6) $\frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}$ $\sin^{2}A+\cos^{2}A = 1$

7) $\frac{1}{\sin^{2}A-\sin^{4}A}$ Result

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