All categories

3 years ago

A right triangle has one 64degree angle and one 90 degree angle

Mathematics

1 answer:

melamori03 [73]3 years ago

7 0

Answer:

I dont know what your asking, for the other angle? Ig so. Answer: THE OTHER ANGLE IS 26. :)

Step-by-step explanation:

64 + 90 = 154.

All triangles add up to 180 degrees.

180-154 = 26.

You might be interested in

72 inches=___ yards please and thank you for your help

I am Lyosha [343]

We know that:

$1yd=36in\text{.}$

Then:

$1in=\frac{1}{36}yd\text{.}$

Therefore:

$72in=72\cdot(\frac{1}{36}yd)\text{.}$

Simplifying the above result we get:

$72\cdot\frac{1}{36}yd=2yd\text{.}$

Answer:

$72\text{inches}=2\text{yards.}$

6 0

1 year ago

What is 14.1% of the 132 mL rounded to the nearest 10th

Anastasy [175]

132 x 14.1% = 18.612

So 18.612 rounded to 18.6

5 0

2 years ago

The equation h=kp describes h, the height of a stack of p pennies. A stack of 15 pennies is 24 millimeters tall. What is the val

slamgirl [31]

You plug in the values so it would be 24=15k. Divide by 15 on both sides so k=24/15=1.6. :)

8 0

2 years ago

Find the area of each polygon

sweet [91]

Answer:

5 in^2

Step-by-step explanation:

Area of square: 2*2=4

Area of triangle: 2*1/2=1

4+1=5

4 0

3 years ago

Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi

boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Description in words of the parameter p

$p$ represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that have experienced bullying

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.