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3 years ago

Answer the question based on the data in the two-way table.

Mathematics

2 answers:

kirill [66]3 years ago

6 0

Answer:

...

Step-by-step explanation:

umm... honestly we will NEVER use this in the real world ‍♂️

liubo4ka [24]3 years ago

5 0

The answer is probably c

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The Basketball Boosters Club plans a pancake supper to raise $1,200. They can serve 240 people. They

wolverine [178]

$\huge{ \mathfrak{ \underline{ Answer} \: \: ✓ }}$

let the number of

adults be x

children be y

Total number of people : adults + children

x + y = 240

x = 240 - y - [1]

Total money earned from adults :

6 × x = 6x

Total money earned from children :

2 × y = 2y

Therefore, total money = money earned from each Adult and children.

6x + 2y = 1200 -[2]

Now, let's plug the value of x from equation [1] into equation [2]

6 (240 - y) + 2y = 1200

1440 - 6y + 2y = 1200

-4y = 1200 - 1440

-4y = - 240

y = 60

let's plug the value of y in equation [1]

x = 240 - y

x = 240 - 60

x = 180

Hence, we get :

total adults = x = 180

total children = y = 60

Correct option is C

_____________________________

$\mathrm{ ☠ \: TeeNForeveR \: ☠}$

7 0

3 years ago

PLEASE ANSWER AS QUICKLY AS POSSIBLE!!

Romashka [77]

Answer:

y=-3x-3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Monthly sales of an SUV model are expected to increase at the rate of S′1t2 = -24t 1>3 SUVs per month, where t is time in mon

uysha [10]

The company will continue to manufacture this model for 19 months.

The question is ill-formatted. The understandable format is given below.

An SUV model's monthly sales are anticipated to rise at a rate of

$S'(t)=-24^{1/3}$ SUVs each month, where "t" denotes the number of months and "S(t)" denotes the monthly sales of SUVs. When monthly sales of 300 SUVs are reached, the business intends to discontinue producing this model.

Find S if monthly sales of SUVs are 1,200 at time t=0 (t). How long will the business keep making this model?

Given $S'(t)=-24^{1/3}$ ... ... (1)

Condition (1) at t=0; s(t) =1200

We find S(t)=300 then t=?

a) We find S(t)

from $S'(t)=-24^{1/3}$

$\implies \frac{dS(t)}{dt}=-24t^{1/3} ~~[\because X'(t)=\frac{dX}{dt} \\\implies dS(t) = -24t^{1/3}dt\\$

On Integrating both sides

$S(t)=-18t^{4/3}+c ~...~...~(2)$

Now, at t=0 then S(t)=1200

So, from (2)

1200=0+c

⇒c=1200

$\therefore$ from eq (2)

$S(t)=-18t^{4/3}+1200 ~...~...~(3)$

b) Considering that the firm intends to cease production of this model once monthly sales exceed 300 SUVs.

So, take S(t)=300

from eq (2) $300=-18t^{4/3}+1200$

$t^{4/3}=\frac{1200-300}{18}\\=\frac{900}{18}=50\\\implies t=50^{3/4}\\\implies t=18.8030$

Hence the company will continue 18.8020 months.

Learn more about integration here-

brainly.com/question/18125359

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8 0

2 years ago

What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15

Aneli [31]

First of all we have to arrange the data in ascending order as shown below:

28, 40, 43, 43, 45, 50, 50

Total number of values = 7

Since the number of values is odd, the median will be the middle value i.e. 4th value which is 43. Median divides the data in two halves:

1st Half = 28, 40, 43
2nd Half = 45, 50, 50

Q1 or the First Quartile is the middle value of the lower or 1st half which is 40.
Q3 or the Third Quartile is the middle value of the upper or second half, which is 50.

IQR or the Inter Quartile Range is the difference of Q3 and Q1.

So, IQR= Q3 – Q1 = 50 – 40 = 10

Thus, IQR for the given data is 10

4 0

3 years ago

Read 2 more answers

Write an inequality for the graph A. x > -3 B. x < -3 c. x > -3 _

earnstyle [38]

Answer:

A. x > -3

Step-by-step explanation:

Well by looking at the graph we can tell that,

the line we can tell that the line goes to the right of of the number line,

Meaning x is greater than -3.

Thus,

x > -3.

Hope this helps :)

5 0

4 years ago