The equation stems from the principle concept of Hooke's Law. After derivation, the general equation for finding the work of a stretch spring is written below:
W = k[(x₂ - x₁) + (x₁ - xn)]
where
k is the spring constant
xn is the natural length of the spring
x₁ is the length after stretching
x₂ is the length after stretching even further
Suppose the spring was only stretched once, then x₁ = x₂. The equation is simplified to:
<em>W = k(x₁ - xn)</em>
Answer:
<h3>160</h3>
Step-by-step explanation:
Divide 7,200 by 45
h(x) = -2x2 + 12x - 3?
The axis of symmetry is :
x = 3
Hope this helps.
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Davinia.
Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
Answer:
159.8195397043133
Step-by-step explanation:
2²⁰
------------------ = 159.8195397043133
3⁸