Answer:
See Below.
Step-by-step explanation:
We are given the function:
And we want to show that it has at least one zero between <em>x</em> = 1 and <em>x</em> = 2.
Because the function is a polynomial, it is everywhere continuous.
Evaluate the function at <em>x</em> = 1 and <em>x</em> = 2:
And:
Therefore, because the function changes signs from <em>x</em> = 1 to <em>x</em> = 2 and is continuous on the interval [1, 2], by the intermediate value theorem, there must exist at least one zero in the interval.
<span>-2x^2-x+7=0
Variable with the highest degree's (exponent) constant, -2 is a, next variable's constant, -1 is b, the constant or number without a variable, 7 is c
using substitution put the numbers into the formula
</span>(-b±√(b^(2)-4ac))/(a^(2))
(-(-1)±√((-1)^(2)-4(-2)(7))/((-2)^(2)) simplify
(1±√(1+56))/4
1±√(57)/4 is your answer
The answer is 5 cause two less then 7 is 5.
I have solved the answer in the pic below, hope it helpss!!!!
Answer:
i think its slope and initial value, so sorry if its wrong
Step-by-step explanation:
