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3 years ago

9

Mean definition in math

2 answers:

Vaselesa [24]3 years ago

7 0

Hi there...

The mean is the average of the numbers.

If you more questions about Mean, I'll be glad to help you.

Have a nice day.

sdas [7]3 years ago

3 0

the mean is the average number of a set of numbers ., for example if the numbers in a group or 223-334-4444 and 5 the mean would be 4

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What is the product of 1/2x-1/4 and 5^2-2x+6 <br> Show work please need an answer fast

kaheart [24]

1/8 for the first one and second one is 23 times 6

7 0

3 years ago

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What's the surface area ratio & the volume ratio??<br><br> please help me ASAP!!

Ulleksa [173]

Answer:

Step-by-step explanation:

Volumes of two spheres A and B = 648 cm³ and 1029 cm³

Things to remember:

1). Scale factor of two objects = $\frac{r_1}{r_2}$ [ $r_1$ and $r_2$ are the radii of two circles]

2). Area scale factor = $\frac{(r_1)^2}{(r_2)^2}$

3). Volume scale factor = $\frac{(r_1)^3}{(r_2)^3}$

Volume scale factor Or Volume ratio = $\frac{V_A}{V_B}$

$\frac{(r_1)^3}{(r_2)^3}= \frac{648}{1029}$

$\frac{r_1}{r_2}=\sqrt[3]{\frac{648}{1029} }$

$\frac{r_1}{r_2}=\frac{6(\sqrt[3]{3})}{7(\sqrt[3]{3})}$

$\frac{r_1}{r_2}=\frac{6}{7}$

Therefore, scale factor = $\frac{r_1}{r_2}=\frac{6}{7}$

≈ 6 : 7

Area scale factor Or area ratio = $(\frac{r_1}{r_2})^2=(\frac{6}{7})^2$

= $\frac{36}{49}$

≈ 36 : 49

Volume scale factor or Volume ratio = $\frac{648}{1029}$

= $\frac{216}{343}$

≈ 216 : 343

4 0

3 years ago

. A trader bought A TV set for Birr 2000 and sold it at loss of 11/2% what:was the selling price?

olga nikolaevna [1]

Answer:

1890

Step-by-step explanation:

Loss = 11/2 % = 5.5 %

Cost price = 2000

Loss = 5.5% of cost price

= 5.5% * 2000

$= \frac{5.5}{100}*2000\\\\= 5.5*20\\= 110$

Selling price = Cost price - loss

= 2000 - 110

= 1890

6 0

3 years ago

I have know idea what to do

Savatey [412]

Sorry, please tell me what the fraction is because I can't see it

7 0

3 years ago

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Rewrite the expression -2a(a+b-5)+3(-5a+2b)+b(6a+b-8)

Nimfa-mama [501]

First separately:
$-2a(a+b-5) = -2a^{2}-2ab+10a$
$3(-5a+2b) = -15a + 6b$
$b(6a+b+8) = 6ab+b^{2}+8b$

Then you add then all together and get:
$-2a^{2}-2ab+10a-15a + 6b+ 6ab+b^{2}+8b =$
$-2a^{2}-5a+4ab+14b+b^{2}$

5 0

3 years ago

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