We are searching for a number that, when these operations are performed, will have an answer of 7. Here are the operations: add
1 answer:
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Answer:
- a ≈ 27.65; B = 28°; c ≈ 19.17
- a ≈ 163.30; B = 120°; c ≈ 59.77
- A = 13°; b ≈ 0.3874; c ≈ 1.3737
Step-by-step explanation:
As long as you're seeking outside help, the use of a suitable tool is appropriate. Many graphing calculators, apps, and web sites are available for solving triangles.
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Here, you're given two angles and a side. The third angle is the difference from 180° of the sum of the other two. For example, in the first problem, ...
B = 180° -A -C = 28°
The missing sides are found using the law of sines. Since you are given a side, use that as the reference, and its opposite angle as the reference angle. Then you have ...
side = sin(opposite angle)×<em>((reference side)/sin(reference angle))</em>
Note that the factor in italics remains the same for both remaining sides.
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In the first problem, this becomes ...
a = sin(112°)·14/sin(28°) ≈ 27.65
c = sin(40°)·14/sin(28°) ≈ 19.17
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The remaining problems are worked in similar fashion.
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<em>Comment on triangle solutions</em>
These are straightforward because you're given two angles. If you're given two sides and an angle, the solution method varies depending on which angle you're given (opposite the long side, the short side, or the unknown side). In the last case, the law of cosines is involved. In the second case, there are likely two solutions. Once you have two angles, you can proceed as above.
Find total number of integers.
Find how many integers is divisible by 2.
Eliminate even numbers.
11, 13, 15,..., 57, 59
This array contains 51 - 26 = 25 numbers.
Eliminate numbers before the first number divisible by 3 and after the last number divisible by 3.
15, 17, 19,..., 55, 57
This array contains 25 - 3 = 22 numbers.
Now we should eliminate numbers divisible by 3: 15, 21, 27...
There are 8 such numbers.
Therefore, there are 25 - 8 = 17 numbers that <span>can be evenly divided by neither 2 nor 3</span>
Find how many integers is divisible by 2.
Eliminate even numbers.
11, 13, 15,..., 57, 59
This array contains 51 - 26 = 25 numbers.
Eliminate numbers before the first number divisible by 3 and after the last number divisible by 3.
15, 17, 19,..., 55, 57
This array contains 25 - 3 = 22 numbers.
Now we should eliminate numbers divisible by 3: 15, 21, 27...
There are 8 such numbers.
Therefore, there are 25 - 8 = 17 numbers that <span>can be evenly divided by neither 2 nor 3</span>