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Montano1993 [528]
3 years ago
11

If I divide xy by y am I left with just x

Mathematics
1 answer:
Olin [163]3 years ago
5 0

xy/y equals x. you just cancel the common factor y

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1,290=h/10+h/5 What is h?​
alekssr [168]

Answer:

4300

h/10 + 2h/10

= 1290

3h/10 = 1290

3h = 12,900

h = 4300

6 0
3 years ago
Read 2 more answers
The scores for a basketball team are 72, 84, 102, 73, 90 and 83. the scores for the next two matches bring the average up to 90.
aniked [119]
72 + 84 + 102 + 73 + 90 + x
OVER
9
EQUALS 90
6 0
3 years ago
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I NEED HELP <br><br>Thank you​
soldi70 [24.7K]

Answer:

tha answer is leter C thanks po

Step-by-step explanation:

thanks you po ??

5 0
3 years ago
Between what two integer powers of 2 does 2√7 lie?
prisoha [69]

Answer:

Between 5 and 6

Step-by-step explanation:

Integers refer to positive whole numbers.

Firstly, we need to know the value of the surd

By calculating, the value of the surd is 5.29

What this mean is that the surd is between the values of 5 and 6

It is slightly greater than 5 and not up to 6

5 0
3 years ago
The number of laughs (denoted by L) can be defined as a function of the number of jokes (denoted by J), the amount of knowledge
Blababa [14]

Answer:

L = f(J, K, F)

L = (JK²)/F

So, as the formula appears, the appropriate units will be option A.

Unit for number of laughs = (jokes*knowledge²) / familiarity

Just like the formula suggests.

Step-by-step explanation:

Complete Question

The number of laughs (denoted by L) can be defined as a function of the number of jokes (denoted by J), the amount of knowledge about the joke material (denoted by K) and the familiarity with the jokes (denoted by F) using this formula: L = (JK²)/F

Select an appropriate unit for number of laughs:

A) (jokes*knowledge²) / familiarity

B) familiarity / (jokes*knowledge²)

C) familiarity² / (jokes*knowledge)

D) (jokes*knowledge) / familiarity²

Solution

L = f(J, K, F)

where

L = number of laughs

J = number of jokes

K = amount of knowledge about the joke material

F = familiarity with the jokes

Analysing how the dependent variable depends on each of the independent variables.

- Number of jokes

The number of laughs will increase with the number of jokes and vice versa. It can be stated that there is a direct variation between the number of laughs and number of jokes.

- Amount of knowledge about the joke material

The more one understands the joke material, the funnier the joke. In fact, the joke can be termed funnier when one understands the joke material deeply. The direct variation of number of laughs to knowledge about joke material isn't just enough, the number of laughs varying directly as the square of the knowledge of joke material seems more fitting.

- Familiarity with the joke

The more familiar one is with a joke, the less funny it is. Hence, it's an inverse relationship between number of laughs and the familiarity with the joke.

L = (JK²)/F

So, as the formula appears, the appropriate units will be

(jokes*knowledge²) / familiarity

Just like the formula suggests.

Hope this Helps!!!

8 0
3 years ago
Read 2 more answers
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