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OLEGan [10]
3 years ago
5

James walks every day at the same rate of speed. On Monday, he walked 3.5 miles in in half an hour Tuesday it took him 4 hours t

o walk 28 miles. On Friday, James walked 56 miles in 8 hours. What is James constant rate of speed?
Mathematics
2 answers:
boyakko [2]3 years ago
8 0

The speed is defined as the ratio between the distance you cover and the time it takes you to cover that distance.

So, in this case, we have

s = \dfrac{3.5}{0.5} = \dfrac{28}{4} = \dfrac{56}{8} = 7\text{ mph}

Tems11 [23]3 years ago
3 0

to find james’ constant rate of speed, you can divide miles by hours (m/h)

28 miles / 4 hours = 7

56 miles / 8 hours = 7

3.5 is half of 7, so we know that’s true as well

this means james’ constant rate of speed would be 7 mph

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Answer:

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Step-by-step explanation:

Given the solution to the differential equation y'' + 25y = 0 to be

y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.

According to the boundary condition y(0) = 2, it means when x = 0, y = 2

On substituting;

2 = c1cos(5(0)) + c2sin(5(0))

2 = c1cos0+c2sin0

2 = c1 + 0

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Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given

y(x) = c1cos5x + c2sin5x

y'(x) = -5c1sin5x + 5c2cos5x

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On substituting;

9 = -5c1sin5π + 5c2cos5π

9 = -5c1(0) + 5c2(-1)

9 = 0-5c2

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c2 = -9/5

Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation

y = c1 cos(5x) + c2 sin(5x) will give

y = 2cos5x-9/5sin5x

The final expression gives the required solution to the differential equation.

3 0
3 years ago
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Step-by-step explanation:

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3 years ago
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Leokris [45]
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