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Vlad1618 [11]
3 years ago
8

Which is the solution of the quadratic equation (4y – 3)2 = 72? y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction a

nd y = StartFraction 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction negative 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 9 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction negative 3 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 9 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 StartRoot 2 EndRoot Over 4 EndFraction
Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

y = \frac{3 + 6\sqrt{2} }{4} and y = \frac{3 - 6\sqrt{2} }{4}

y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction

Step-by-step explanation:

The given quadratic equation is (4y - 3)² = 72

We have to solve this equation for y.

Now, 4y - 3 = ± 6√2

⇒ 4y = 3 ± 6√2

⇒ y = \frac{3 + 6\sqrt{2} }{4} and y = \frac{3 - 6\sqrt{2} }{4}

Therefore, the solution is y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction (Answer)

Morgarella [4.7K]3 years ago
6 0

Answer:

c

Step-by-step explanation:

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