Answer:
Explanation:
- cancerous cells continue to grow and divide
- there are a variation in the size of cancer cells
- the nucleus of a cancer cells is darker and larger than a non-cancerous cell
- the is an abnormal amount of chromosomes i a cancerous cell
- cancerous cells have chromosomes that aren't neat and ordered whereas non - cancerous cells are
Hope that helped :)
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The answer you're looking for is <u>Involves actual transfer of electrons.</u> I hope that this helps you! Please leave brainliest answer if you can!
Answer:
1.31 cM
Explanation:
Total offspring = 2205
Since two genes are involved, F1 progeny should have four types of combination. Out of them two are 17 and 12 which definitely means they are in lesser number. Since recombinants are always less than parental progeny in linkage, the given two types are recombinants.
Recombination frequency = (Number of recombinants / Total progeny) * 100
= [ ( 17 + 12 ) / 2205 ] * 100
= ( 29 / 2205 ) * 100
= 1.31 %
Map distance = Recombination frequency
Hence, distance between two genes = 1.31 cM
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