$a _{n} = a _{1} + (n - 1)d \\ a _{41} = - 534 \\ a _{54} = - 708 \\ a _{41} = a _{1} + (41 - 1)d = - 534 \\ a _{1} + 40d = - 534 \: \: ...(1)\\ a _{54} = a _{1} + (54 - 1)d =- 708 \\ a _{1} + 53d = - 708 \: \: ...(2)$

Try to solve the similtanious equation to find the first term and the common difference, then use that information to figure out the 80th term... Update me if you need further help ...

7 0

2 years ago

The store currently has seven rackets of each version. What is the probability that all of the next ten customers who want this

Mila [183]

The probability that all of the next ten customers who want this racket can get the version they want from current stock is 0.821

<h3>How to solve?</h3>

Given: currently has seven rackets of each version.

Then the probability that the next ten customers get the racket they want is P(3≤X≤7)

Note that If less than 3 customers want the oversize, then more than 7 want the midsize and someone's going to miss out.

X ~ Binomial (n = 10, p = 0.6)

P(3≤X≤7) = P(X≤7) - P(X≤2)

From Binomial Table:

= 0.8333 - 0.012

= 0.821

To learn more about Probability visit :

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6 0

2 years ago

Simora [160]

M >= 85. The >= sign means greater than or equal to.

8 0

2 years ago

Three hamburgers and two hotdogs cost $13. Two hamburgers and four hotdogs cost $14 what is the cost of one hamburger? What is t

Harrizon [31]

Step-by-step explanation:

Let's take cost of 1 hamburger as h and the cost of 1 hot dog as d.

Therefore, we can form the equations:

3h + 2d = 13 and

2h + 4d = 14

2(h +2d) = 14

h + 2d = 7

h = 7 - 2d

By substituting this to the first equation, we get:

3(7 - 2d) + 2d = 13

21 - 4d = 13

4d = 8

d = $2

h = 7 - 2(2)

h = $3

Hence <u>1 hot dog costs $2</u> and <u>1 hamburger costs $3</u>

5 0

3 years ago