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Andreyy89
3 years ago
11

How many real number solutions does the equation have

Mathematics
1 answer:
Ksju [112]3 years ago
5 0
You have to find the discriminat b^2 -4ac

If it is > 0, the function has two real solutions
if it is = 0, the function has one real solution
if it is <0, the function has no real solution

6^2 - 4(7)(3) = 36 - 84 = - 48

Answer c. no solution
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What is 11.375 in faction
Anton [14]
11 3/8 would be the simplified version and 91/8 would be the other way.
6 0
3 years ago
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If you pick a card at random from a well shuffled deck, what is the probability that you get a face card or a spade?
tankabanditka [31]
P(Face card) =16/52 = 4/13
P(Spade) = 13/52 =1/4
P(Face ∪ Spade) = 4/13 + 1/4 = 29/52 = 0.557

7 0
3 years ago
X,y and z are three consecutive even numbers if y^2 - 2 = 2x + 5Z find x,y and z​
Rama09 [41]

Answer:

6, 8, 10

Step-by-step explanation:

x y and z are three consecutive even numbers

it means that you can write y = x + 2

and z = y + 2 = x + 4

so

  y^2-2=2x+5z\\  (x+2)^2-2=2x+5(x+4)\\x^2+4x+4-2=2x+5x+20

  x^2+4x+2=7x+20\\x^2+4x+2-7x-20=0\\x^2-3x-18=0\\(x+3)(x-6)=0(x=-3\ or \ x=6)

so the solutions are

x = 6

y = 8

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6 0
3 years ago
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If the average weight of sophomore boys in Arizona is 140 pounds with a standard
yKpoI14uk [10]

Answer:

Light

Step-by-step explanation:

He is below the standard deviation limits for average or normal.

5 0
3 years ago
A golfer keeps track of his score for playing nine holes of golf​ (half a normal golf​ round). His mean score is 8080 with a sta
solniwko [45]

Answer:

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and 11\sqrt2 respectively.

Step-by-step explanation:

Given that,

For the first 9 holes X:

E(X) = 80

SD(X)=13

For the second 9 holes Y:

E(Y) = 80

SD(Y)=13

For the sum W=X+Y, the following properties holds for means , variance and standard deviation :

E(W)=E(X)+E(Y)

     and

V(W)=V(X)+V(Y)

⇒SD²(W)=SD²(X)+SD²(Y)        [ Variance = (standard deviation)²]

\Rightarrow SD(W)=\sqrt{SD^2(X)+SD^2(Y)}

∴E(W)=E(X)+E(Y) = 80 +80=160

            and

∴SD(W)=\sqrt{SD^2(X)+SD^2(Y)}

              =\sqrt{11^2+11^2}

               =\sqrt{2.11^2}

               =11\sqrt2

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and 11\sqrt2 respectively.

                                               

4 0
3 years ago
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