Answer:
There are 38 premium tickets and 82 regular tickets in a pile.
Step-by-step explanation:
Given,
Total number of tickets = 120
Total amount = $5812
Solution,
Let the number of premium tickets be x.
And the number of regular tickets be y.
Total number of tickets is the sum of total number of premium tickets and total number of regular tickets.
So the equation can be written as;

Again,total amount is the sum of total number of premium tickets multiplied by cost of each premium ticket and total number of regular tickets multiplied by cost of each regular ticket.
So the equation can be written as;

Now We will multiply equation 1 by 25 we get;

Now Subtracting equation 3 from equation 2 we get;

We will now substitute the value of x in equation 1 we get;

Hence There are 38 premium tickets and 82 regular tickets in a pile.
Answer:
B. is your answer
Step-by-step explanation:
First you multiply both sides by "x" and you get
12x - 4 = 3x
now add 4 to both sides and you get
12x = 3x + 4
now subtract "3x" from both sides and you get
9x = 4
divide both sides by 9 and you get
x = 4/9
Given that the point (12,-5) which takes the form (x,y), This implies that:
opposite=-5
adjacent=12
thus using using Pythagorean theorem, the hypotenuse will be:
c^2=a^2+b^2
plugging the values we obtain:
c^2=(12)^2+(-5)^2
c^2=144+15
c^2=169
thus
c=13
but
cos θ=adjacent/ hypotenuse
therefore:
cos θ=12/13
Answer is option . D