Log3(6)=x
6=3^x
log2(6)=xlog2(3)
x=log2(6)/log2(3)
so its B, I know how to do it
It should be the second awnser
The correct answer is P = 0.1357.
In solving for the probability (P) that the 34-year olds
will spend more than $60 on fastfood, the mean and the standard deviation is to
be taken into account. The mean (μ) being the $44 average weekly expenditure; while
the standard deviation (σ) is $14.50. The formula goes this way P(X > 60) =
P( X−μ > 60−44 ) = P ( X−μ/σ > 60−44/14.50).
You just simply divide 7 by 30. The answer would be 0.233333