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faust18 [17]
3 years ago
14

Write the slope-intercept form of the equation of the line described below.

Mathematics
1 answer:
prisoha [69]3 years ago
4 0

The equation of the line is y=-\frac{2}{5}x-5

Explanation:

Given that the line passes through the points (-5,-3)

The slope of the line is m=-\frac{2}{5}

We need to determine the equation of the line.

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Let us substitute the points (-5,-3) and the slope m=-\frac{2}{5} in the above formula.

Thus, we have;

y+3=-\frac{2}{5}(x+5)

Simplifying, we get;

y+3=-\frac{2}{5}x-2

Subtracting 3 from both sides of the equation, we get;

y=-\frac{2}{5}x-5

Hence, the equation of the line in slope - intercept form is y=-\frac{2}{5}x-5

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Step-by-step explanation:

Hey there!

Given;

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RHS:

\frac{f(x)}{g(x)}  =  \frac{ {x}^{2}  + 2x - 1}{3x - 2}

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\frac{f(2)}{g(2)}  =  \frac{ {2}^{2} + 2 \times 2 - 1 }{3 \times 2 - 2}

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Since (f/g)(2) = f(2)/g(2) = 7/4.

<em><u>Proved!</u></em>

<u>Hope </u><u>it </u><u>helps</u><u>!</u>

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