For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:
<h3>What is needed for a discrete random variable to represent a probability distribution?</h3>
The sum of all the probabilities must be of 1, hence:
P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.
Then, considering the table:
P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1
P(X = 0) + P(X = 1) + 0.56 = 1
P(X = 0) + P(X = 1) = 0.44.
Hence one possible example is:
More can be learned about probability distributions at brainly.com/question/24802582
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In a rhombus, all sides are equal.
So for the quadrilateral MNOP to be a rhombus, the given sides have to be equal. THat is
Adding 3x to both sides and addinf 7 to both sides
Now we need to get rid of 7 and for that we do division, that is
Correct option is the second option .
Answer:
a) f g(x) = x³ - 5 x² + x -5
b) g(f(x) = x³ - 5 x² + x -5
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that f(x) = x² + 1 and g(x) = x-5
a)
f(g(x)) = f(x-5) = (x-5)²+1 = x² - 10x +25 +1 = x² - 10 x +26
<u><em>Step(ii):-</em></u>
a) f g(x) = f(x) g(x) = (x² + 1 )(x-5) = x³ - 5 x² + x -5
b) g(f(x) = g(x) f(x) = (x-5) (x²+1) = x³ - 5 x² + x -5
Because 58 is closer to 100 than 0
another example you can see is if it was 10058 and you were asked to round to the nearest hundred you can say 10100
