Yumi spent $34.15 buying stamps. The number of 56-cent stamps she bought was 10 less than 4 times the number of 41-cent stamps.
1 answer:
<h3>Number of 56 cent stamps is 50 and number of 41 cent stamps is 15</h3>
<em><u>Solution:</u></em>
Let "a" be the number of 56 cent stamps
Let "b" be the number of 41 cent stamps
<em><u>The number of 56-cent stamps she bought was 10 less than 4 times the number of 41-cent stamps</u></em>
number of 56-cent stamps = 4 times the number of 41-cent stamps - 10
a = 4b - 10 -------- eqn 1
<em><u>Yumi spent $34.15 buying stamps</u></em>
Therefore,
56a + 41b = 3415 ------- eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
56(4b - 10) + 41b = 3415
224b - 560 + 41b = 3415
265b = 3975
<h3>b = 15</h3><em><u>Substitute b = 15 in eqn 1</u></em>
a = 4(15) - 10
a = 60 - 10
<h3>a = 50</h3>Thus number of 56 cent stamps is 50 and number of 41 cent stamps is 15
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2. A) 8
3. B) 4/15
4. A) 2/9
5.D) 64%
Step-by-step explanation:
1. Since, here the tokens from a bag containing 10 blue tokens, 8 green tokens, and 12 red tokens. The first draw is a green token.
Thus, the total token = 10 blue tokens+ 8 green tokens+ 12 red tokens = 30 token
Therefore, If the first draw is a green token, Then total outcomes that will possible = 30.
2. Since, getting green is an event with 8 favorable outcomes.
Therefore, If the first draw is a green token, Then total favorable outcomes that will possible = 8.
3. The possibility of getting green in first drawn, P(G) =
P(G) =
4. Here, Number of red socks= 5
Number of white socks = 2 and Number of blue socks=3
Therefore total socks = 10
⇒ Probability of picking a pair of red socks,
P(R)=
⇒ P(R)= 2/9
5. Since, here coin is flipped 50 times and lands on heads 32 times.
Therefore, experimental probability that coin will land on heads on the next flip = (total times in which head appears/ total number of experiments) × 100 = (32/50)×100=64%
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