Question

token. How many total outcomes were possible for this event?
A.
8

B.
10

C.
22

D.
30

Marcus randomly draws tokens from a bag containing 10 blue tokens, 8 green tokens, and 12 red tokens. The first draw is a green token. How many favorable outcomes are possible for this event?

A.
8

B.
10

C.
22

D.
30

Marcus randomly draws tokens from a bag containing 10 blue tokens, 8 green tokens, and 12 red tokens. The first draw is a green token. What is the probability of this event?

A. 4/11

B. 4/15

C. 1/2

D. 1/3

There are 5 red socks, 2 white socks, and 3 blue socks in a basket. What is the probability of picking a pair of red socks?

A. 2/9

B. 7/90

C. 1/5

D. 9/100

A coin is flipped 50 times and lands on heads 32 times. What is the experimental probability the coin will land on heads on the next flip?

A.
32%

B.
50%

C.
56%

D.
64%

Answer 1

Answer: 1. D) 30

2. A) 8

3. B) 4/15

4. A)  2/9

5.D) 64%

Step-by-step explanation:    

1. Since, here the tokens from a bag containing 10 blue tokens, 8 green tokens, and 12 red tokens. The first draw is a green token.

Thus, the total token = 10 blue tokens+ 8 green tokens+ 12 red tokens = 30 token

Therefore, If the first draw is a green token, Then total outcomes that will possible = 30.

2. Since, getting green is an event with 8 favorable outcomes.

Therefore,  If the first draw is a green token, Then total favorable outcomes that will possible = 8.

3. The possibility of getting green in first drawn, P(G) = $\frac{8_C_1}{30_C_1}$

P(G) =  $\frac{8}{30} = \frac{4}{15}$

4. Here, Number of red socks= 5

Number of white socks = 2 and Number of  blue socks=3

Therefore total socks = 10

⇒ Probability of picking a pair of red socks,

P(R)= $\frac{5_C_2}{10_C_2} = \frac{10}{45}$

⇒ P(R)= 2/9

5. Since, here coin is flipped 50 times and lands on heads 32 times.

Therefore, experimental probability that coin will land on heads on the next flip = (total times in which head appears/ total number of experiments) × 100 = (32/50)×100=64%