You want to find out the probability of getting a 2 first and getting a 3 on a fair dice;
P(rolling 2 and 3)= (1/6)(1/6) <-- knowing that rolling a 2 has a possibility of 1/6, same with rolling a 3.
Therefore, the probability of getting a 2 and a three or 3 and a two is 1/36
Hope I helped :)
(4+x)+x=22
= 4+2x=22
= 2x = 18
= x = 9.
Gabriel is 9 years old, and Dan is 4 + 9 or 13 years old.
(u^2 - 4) / (u-6)(u-2)
Resriction u ≠ 6 and u ≠ 2 (because the denominator cannot be equal lto zero)
Simplification
u^2 - 4 is a difference of two squares, then you can factor it as the product of (u+2)(u-2). So, you can write the expression as:
(u+2)(u-2) / (u-2)(u-6)
Simplify u -2 (because it appears in the numerator and the denominator)
(u + 2) / (u -6), with u ≠2 and u≠6
Answer:
Step-by-step explanation:
