3 years ago

What is an equation of the line that passes through the point (0, 1) and has a slope of 3

Mathematics

1 answer:

qaws [65]3 years ago

7 0

C because it goes through the point(0,1) and has a slope of 3

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Name: Kadence Eling Date: 21-15-22 Hr. 1st Use a diagram to solve each of the problems below, marks English test had 90 question

FrozenT [24]

Answer:80%

Step-by-step explanation:

18/90 × 100%

=20%

he got 20% of the questions wrong

100% - 20% =80%

=>he got 80% of the questions correct

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2 years ago

Square p and square q

sukhopar [10]

Answer:

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Step-by-step explanation:

But i say Square q

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2 years ago

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Galina-37 [17]

Answer:1/27

Explanation:

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2 years ago

A rectangular lamina of uniform density is situated with opposite corners at (0,0) and (15,4). calculate its radii of gyration a

Sphinxa [80]

First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.

$I_{x}= \int\limits^15_0\int\limits^4_0 {k y^{2} } \, dx dy= \frac{1}{3}k (15-4)^4=4880.33k$

$I_{y}= \int\limits^15_0\int\limits^4_0 {k x^{2} } \, dx dy= \frac{1}{3}k (15-4)^4=4880.33k$

Then, the radii of gyration for

x = √[I_x/m]
y = [I_y/m]

where m = k(15-4)² = 121k. Then,

x = y = [4880.33k/121k] = 40.33

I hope I was able to help you. Have a good day.

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3 years ago

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sesenic [268]

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