The locations, given in polar coordinates, for two planes approaching an airport are (4 mi, 12 degrees) and (3 mi, 73 degrees).
Find the distance between the two planes.
2 answers:
d^2=(4cos12-3cos73)^2+(4sin12-3sin73)^2
d^2≈7.18593
d≈2.68mi (to nearest hundredth of a mile)
D^2=(4cos12-3cos73)^2+(4sin12-3sin73)^2
d^2≈7.18593
d≈2.68mi (to nearest hundredth of a mile)
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