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Aleonysh [2.5K]
3 years ago
13

Solve the set of equations x-y=4 2x+y=9

Mathematics
1 answer:
pochemuha3 years ago
5 0
X - y = 4 (1)
2x + y = 9 (2)
We need to solve for x and y.

Let's find the algebraic value of x using the equation (1):
x-y = 4
add y in both sides
x-y+y = 4+y
x = 4+y

Now let's using this value instead of x in the equation (2):
2x + y = 9
2(4+y) + y = 9
8 + 2y + y = 9
3y + 8 = 9
Subtract 8 from both sides
3y + 8 - 8 = 9 - 8
3y = 1
divide both sides by 3
(3y)/3 = 1/3
y=1/3

Let's use the value of y to find the value x using the equation (1)
x - y = 4
x = y+4
x = 1/3 + 4
x = 13/3

So x = 13/3 and y = 1/3

Let's recheck the answers (very important):
x - y = 13/3 - 1/3 = 12/3 = 4 (correct)
2x + y = 2*(13/3) + 1/3 = 26/3 + 1/3 = 27/3 = 9 (correct)
The answer has been approved.

Hope this helps! :D
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7 0
3 years ago
Martin earned the following scores on his last five tests.
egoroff_w [7]
<span>98, 78 , 84, 75, 91
</span>

The interquartile range formula is the first <span>quartile </span>subtracted from the third quartile:

<span>IQR = Q3 – Q1.</span>

<span><span>****************************************************
Step 1: Put the numbers in order.
75, 78, 84, 91, 98

</span><span><span>Step 2: </span><span>Find the median</span>.
</span></span>75, 78, 84, 91, 98
<span>
<span><span>Step 3: </span><span>Place parentheses around the numbers above and below the median. </span>
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
</span></span>(75, 78), 84, (91, 98)
<span>
<span><span>Step 4: </span>Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
</span></span>(75, 78), 84, (91, 98)

<span>*(75, 78) ---> (75 + 78) </span>÷ 2 = 76.5
<span>*(91, 98) ---> (91 + 98) </span>÷ 2 = 94.5
<span>
<span><span>Step 5: </span>Subtract Q1 from Q3 to find the interquartile range.
94.5 – 76.5 = 18

IQR = 18</span></span>
7 0
4 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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A square was enlarged by the scale factor 2 the new square has sides of 12cm find the area of the original
BlackZzzverrR [31]

Answer:

36cm^2

Step-by-step explanation:

Since the square was enlarged by a scale factor 2, sides of the old square = 12/2

= 6

Area of the original quare = L x L

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8 0
4 years ago
Express x% of 4 plus y% of 5 as a percentage of 11
djverab [1.8K]
X% of 4 = x*4/100 = 0.04x

y% of 5 = x*5/100 = 0.05y

x% of 4 + y% of 5 = 0.04x + 0.05y

How you express a number, n, as percentage of 11?: [n/11]*100= 9.10n %

Then make n = 0.04x + 0.05y

9.10n %= 9.10[0.04x + 0.05y] %= (0.3656x + 0.455y)%

.


 



4 0
4 years ago
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