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kap26 [50]
3 years ago
7

Sorrh Guys im not good at math like at all

Mathematics
1 answer:
Anni [7]3 years ago
7 0
Cos(B) = adjacent / hypotenuse
Cos(B) = 11/27
Cos(B) = 0.4074
B = Cos-1(0.4074)
Put this into your calculator like this.
2nd function Cos-1
(
0.4074
=
65.96 <<<<<< answer
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Solve each of the following quadratic equations.
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Read 2 more answers
Can anybody help me with this?<br> Algebra 1
Marina CMI [18]

Answer:

see below

Step-by-step explanation:

7. f(x) = mx + b; b acts as the vertical shift moving the graph up if b is positive and down if b is negative.

f(x) = x-2 has shifted the graph of f(x) down 2 units.

g(x) = x + 7 has shifted the graph up 7 units.

If f(x) is changed to g(x) the vertical shift has gone from -2 to + 7 or (7-(-2) = 9 units up

8. f(x) = mx stretches the graph by a factor of m if m > 0 and compresses the graph by a factor of m if 0<m<1

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8 0
3 years ago
What is 0.04 km, 420 cm, 4,600 mm, and 4.3 meters in order from least to greatest
Paul [167]

Answer:

420 cm, 4.3 meters, 4600 mm, 0.04 km

Step-by-step explanation:

We can solve this by converting each to the same unit. I will be using meters.

0.04 km

1 km = 1000 meters

1000 meters / 1 km = 1

multiply 0.04 km by 1 = 1000 meters / 1 km , keeping the km at the bottom to cross out

0.04 km * 1000 meters / 1 km = 40 meters

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100 cm = 1 meter

1 meter / 100 cm = 1

multiply 420 cm by this, keeping cm at the bottom so it crosses out

420 cm * 1 meter / 100 cm = 4.2 meters

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4600 mm * 1 meter / 1000 mm = 4.6 meters

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420 cm, 4.3 meters, 4600 mm, 0.04 km

6 0
2 years ago
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Answer:

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Step-by-step explanation:

The zeros of a function are the x-intercepts or roots where the function crosses the x-axis. To find them, graph the function x^2 +2x-180 and zoom in on the x-axis.

See attached picture.

6 0
3 years ago
If m∠D + m∠E = 180°, then ∠D and ∠E are classified as what kind of angles?
Archy [21]
The other person is literally wrong. The answer is D. Supplementary because two angles that add up to 180 are supplementary angles.
3 0
2 years ago
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