All categories

4 years ago

Which of the following is equivalent to the quadratic equation below after completing the square?

Mathematics

1 answer:

Natalka [10]4 years ago

3 0

X^2 + 4x = 0
x^2 + 4x + 4 = 0 + 4
(x + 2)^2 = 4

You might be interested in

D’Quan’s grandmother made a quilt for his bed. The quilt is

erik [133]

4.4652 square feet. you just multiply the two

6 0

4 years ago

What is the answer to this?

amm1812

Answer:

solution,

BC=8.4 cm

AB=12 cm

BD=4.1 cm

We have to find out: AC ,CD

using Pythagoras theorem:

In ∆ABC ,<B=90°

${(ac)}^{2} = {(ab)}^{2} + {(bc)}^{2} \\ {(ac)}^{2} = {(12)}^{2} + {(8.4)}^{2} \\ {(ac)}^{2} = 144 + 70.56 \\ {(ac)}^{2} = 214.56 \\ ac = \sqrt{214.56} \\ ac = 14.64 \: cm$

Similarly,

In ∆BCD, CB=90

$cd = \sqrt{ {(8.4)}^{2} + {(4.1)}^{2} }$

$= \sqrt{70.56 + 16.81} \\ = \sqrt{87.37} \\ = 9.34 \: cm$

Perimeter:

AC+CD+AD

=14.64+9.34+(12+4.1)

=40.08

= 40.1 cm

Hope this helps...

Good luck on your assignment..

7 0

3 years ago

There are 8 girls and 5 boys on the math team.Which ratio correctly describes the relationship between boys and girls on the mat

krok68 [10]

8:5 because it’s girls to boys, and that’s the lowest you can simplify them

7 0

3 years ago

HELP ASAP !!

Aleks [24]

Answer:

Step-by-step explanation:

total money = $2.25 = 225 cents

types of denomination in coins or cents are dimes and nickels

dime = 10 cents , nickel = 5 cents

twice of dimes to nickels

let no of dimes = x and no of nickels = y

our equation

10x + 5y = 225

x = 2y

10(2y) + 5y = 225

20y +5y = 225

25 y = 225

y=9

x =2y 2x9 = 18

so the number of dimes = 18 and nickels = 9

cross verification:

10x18 + 5x9 = 180 +45 = 225

6 0

3 years ago

(a) Find an approximation to the integral 2 (x2 − 4x) dx 0 using a Riemann sum with right endpoints and n = 8. R8 =

denpristay [2]

Answer:

Step-by-step explanation:

$\int\limits^2_0 {(x^2-4x)} \, dx$ n=8 f(x) = x² - 4x

convert [0,2] into 8 subintervals

width of each interval is

$\delta x =\frac{2-0}{8}=0.25$

All subintervals are:

[0, 0.25], [0.25, 0.5], [0.5, 0.75], [0.75, 1], [1, 1.25], [1.25, 1.5], [1.5, 1.75] and [1.75, 2]

Let, $x_i$ be the right end point of each interval i=1,..8

$x_1=0.25, x_2=0.5, x_3=0.75, x_4=1, x_5=1.25, x_6=1.5, x_7=1.75, x_8=2$

Reiman sum is

$R_8=\delta x[f(x_1)+f(x_2)+...f(8)]\\\\0.25[f(0.25)+f(0.5)+...+f(2)]\\\\0.25\times[-23.25]\\=-5.8125$

8 0

3 years ago