Answer/Step-by-step explanation:
Part A:
![Key:\left[1 Adult = 4 Student]](https://tex.z-dn.net/?f=Key%3A%5Cleft%5B1%20Adult%20%3D%204%20Student%5D)
<u> 12 Student = 3 Adult</u>
<u>24 Student = 6 Adult</u>
<u>40 Student = 10 Adult</u>
Part B:
33 Student
Hence, divide 33 by 4 = 8 with a remainder of 1.
Therefore, 8 Adult and for the remainder 1 student either one Adult takes 5 Student or Needed 9 Adult.
Answer:
1
Step-by-step explanation:
The rules for significant figures are:
- Non-zero digits are always significant.
- Zeros between significant digits are also significant.
- Trailing zeros are significant only after a decimal point.
In 13822, all of the digits are non-zero. So the first significant figure is 1.
Are you looking for the name of the method? If so, it's called completing the square.
Answer:
a)
We know that:
a, b > 0
a < b
With this, we want to prove that a^2 < b^2
Well, we start with:
a < b
If we multiply both sides by a, we get:
a*a < b*a
a^2 < b*a
now let's go back to the initial inequality.
a < b
if we now multiply both sides by b, we get:
a*b < b*b
a*b < b^2
Then we have the two inequalities:
a^2 < b*a
a*b < b^2
a*b = b*a
Then we can rewrite this as:
a^2 < b*a < b^2
This means that:
a^2 < b^2
b) Now we know that a.b > 0, and a^2 < b^2
With this, we want to prove that a < b
So let's start with:
a^2 < b^2
only with this, we can know that a*b will be between these two numbers.
Then:
a^2 < a*b < b^2
Now just divide all the sides by a or b.
if we divide all of them by a, we get:
a^2/a < a*b/a < b^2/a
a < b < b^2/a
In the first part, we have a < b, this is what we wanted to get.
Another way can be:
a^2 < b^2
divide both sides by a^2
1 < b^2/a^2
Let's apply the square root in both sides:
√1 < √( b^2/a^2)
1 < b/a
Now we multiply both sides by a:
a < b
Answer:
Step-by-step explanation:
length=4×28=112 mm=11.2 cm
three centers form an equilateral triangle each side=2×28=56mm=5.6 cm
to find the height
h=√(5.6²-2.8²)=2.8√3
width=2.8+2.8√3+2.8=5.6+2.8√3=2.8(2+√3)
area=11.2×2.8(2+√3)≈117.03 7cm²≈117 cm²
