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sladkih [1.3K]
2 years ago
8

It measures the space inside a 2-dimensional figure

Mathematics
1 answer:
Verdich [7]2 years ago
5 0

Answer:g

Step-by-step explanation:

Does

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Write as a decimal : twenty-eight ten- thousandths
Ratling [72]

Answer:

28.0001

Step-by-step explanation:

im pretty sure

6 0
3 years ago
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Assume that females have pulse rates that are normally distributed with a mean of beats per minute and a standard deviation of b
snow_tiger [21]

Answer:

a) This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b) P-value of Z when X = 76 subtracted by the p-value of X = 68.

c) Because the underlying distribution(pulse rates of females) is normal.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean \mu, standard deviation \sigma.

standard deviation of beats per minute.

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is between A beats per minute and B beats per minute.

This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b. If 4 adult females are selected, find the probability that they have pulse rates with a mean between 68 beats per minute and 76 beats per minute.

Sample of 4 means that we have n = 4, s = \frac{\sigma}{\sqrt{4}} = 0.5\sigma

The formula for the z-score is:

Z = \frac{X - \mu}{\sigma}

Z = \frac{X - \mu}{0.5\sigma}

Z = 2\frac{X - \mu}{\sigma}

This probability is the p-value of Z when X = 76 subtracted by the p-value of X = 68.

c. Why can the normal distribution be used in heartbeat even the sample side does not exceed 30?

Because the underlying distribution(pulse rates of females) is normal.

3 0
2 years ago
Geometry proofs <br> Need help!!
Andrew [12]

Angles ∠MOK and ∠NOL are identical by opposite angle theorem.

∠M = ∠N through given information

∠MKO and ∠NLO are congruent. Since the other two angles of each triangle are equivalent, the last angle must be equivalent to the last angle of the other triangle. (180 - ∠1 -∠2 = ∠3); you could also prove ∠MKO  = ∠NLO by stating that the opposite sides of the two angles are congruent.

ΔMKO and ΔNLO by Angle-Angle-Side theorem

since ΔMKO and ΔNLO, all corresponding parts of both triangles are congruent, so therefore MO ≅ NO

8 0
3 years ago
The Smiths leave Indiana at 6:00 am to travel to Georgia. They stop for 4 breaks totaling 3 hours and stop to visit some friends
satela [25.4K]
It's 975 because they traveled for 17 hours and had stopped for 2 hours do 17-2=15, so 15×65=975
6 0
3 years ago
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Brainliest reward …… please quick
strojnjashka [21]

Answer:

3 boxes of fertilisers.

Solving steps:

<u>Part A</u>:

Area of the garden, rectangle:

Length * Width

12 * 7

84 m²

Area of patio:

\sf{\frac{1}{2}  * base *height

\sf{\frac{1}{2}  * 6*3

\sf{9 m²

Area of grass:

Area of the garden - Area of patio

84 m² - 9 m²

75 m²

<u>Part B</u>:

32 m² ↔  1 box

1 m²    ↔ \sf{ \frac{1}{32} box

75 m²  ↔ \sf{ \frac{1}{32} *75 boxes

75 m²  ↔ 2.34375 boxes

  • As she cannot buy exact 2.34375 boxes.

She should buy 3 boxes of fertilisers.

6 0
2 years ago
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