Ask question

Ask question

All categories

2 years ago

9

Diana designs a paper number cube (dice) to play a game called "make 48". If each pair of opposite faces has a product of 48. Wh

at are the missing numbers on the number cube?

2 answers:

enyata [817]2 years ago

6 0

The missing numbers are 24

Tema [17]2 years ago

5 0

The missing numbers are 24.
Hope this helps!

You might be interested in

Jessie has some nickels, dimes, and quarters in her bank. The number of coins is 30. The expression 0.05n + 0.10d + 0.25q repres

goldfiish [28.3K]

Answer:

n = 12 nickels

d = 11 dimes

q = 7 quarters

Step-by-step explanation:

.05n + .1d + .25q = 3.45

n + d + q = 30

n = q + 5

n = 12

d = 11

q = 7

8 0

2 years ago

Please help me with this geometry question !!!

Inessa05 [86]

Answer:

see explanation

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 90°

a point (x, y ) → (- y, x ), thus

P(1, - 1 ) → P'(1, 1 )

Q(3, - 2 ) → Q'(2, 3 )

R(3, - 4 ) → R'(4, 3 )

8 0

2 years ago

Brian has 75 pieces of candy 45 pieces of his candy or chocolate what percentage of his candy is chocolate

Alik [6]

Answer:

60%

Step-by-step explanation:

45 pieces out of 75 pieces are chocolate

45/75

Divide: 45/75 = 0.6

To get percentage from a decimal, move the decimal point to the right two place values

0.6 => 60%

60% of his candy are chocolate

4 0

3 years ago

Read 2 more answers

a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.

ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: $\mathbf{Length = a -5}$ and $\mathbf{Width = a^2 + 5a + 25}$

The area is given as:

$\mathbf{Area = a^3 - 125}$

Express 125 as 5^3

$\mathbf{Area = a^3 - 5^3}$

Apply difference of cubes

$\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}$

$\mathbf{Area = (a - 5)(a^2 + 5a + 25)}$

The area of a rectangle is:

$\mathbf{Area = Length \times Width}$

So, by comparison:

$\mathbf{Length = a -5}$

$\mathbf{Width = a^2 + 5a + 25}$

Read more about areas at:

brainly.com/question/3518080

6 0

2 years ago

The three sides of a triangle are n, 3n+3, and 2n+11. If the perimeter of the triangle is 50 inches, what is the length of each

mylen [45]

Answer:

6, 21, and 23 inches

Step-by-step explanation:

The perimeter of a triangle is equal to the sum of all side lengths in that triangle. We're given the perimeter as 50 inches, and the side lengths as n, 3n + 3, and 2n + 11.

This means that we can algebraically solve the equation $n + 3n + 3 + 2n + 11 = 50$

Step 1: Combine like terms.

$(n+3n+2n) + (3+11) = 50$
$6n + 14 = 50$

Step 2: Subtract 14 from both sides.

$6n + 14 - 14 = 50 - 14$
$6n = 36$

Step 3: Divide both sides by 6.

$6n/6 = 36/6$
$n = 6$

Step 4: Plug in the value of n as 6 in each side.

$(6) + (3(6) + 3) + (2(6)+11) = 50$
$(6) + (18+3) + (12+11) = 50$
$(6) + (21) + (23) = 50$

Therefore, the side lengths are 6, 21, and 23 inches.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0

2 years ago