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lidiya [134]
4 years ago
5

Someone pls Help me out!!!

Mathematics
2 answers:
Ipatiy [6.2K]4 years ago
5 0
Yup ....................
Law Incorporation [45]4 years ago
3 0

Answer:

Gasoline = 10.2 * 3.80= 38.76

Water= 3 * 3.98 = 11.94

Ice- 3 * 1.99 = 5.97

Oranges= 1 * 8.89 = 8.89

Step-by-step explanation:

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At the fair a pack of 25 ride tickets cost $43.75.<br><br> What is the price per ticket?
SCORPION-xisa [38]
You divide 25 by 43.75 and you will get 1.75
8 0
3 years ago
Work out the value of 3c-4d when c=5 and d= ½
nikdorinn [45]
3(5) - 4(1/2)
15 - 2 = 13
4 0
3 years ago
Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
3 years ago
Find the solution of this system of equations. Separate the x- and y-values with a comma.
natita [175]
X=0+y6x−5y=23
6x=23+5yx=23+5y6
now sub x=23+5y6in x=0+ywe get23+5y6=0+ymultiple both side of the equation by 6..we get23+5y=6ynow we solve for y..23=6y−5yy=23now since we find y...we can find x..by by substituting y=23 in the 1st or 2nd equation...so, using equation 1x=0+yx=0+23x=23

Hopefully this helps :)
3 0
3 years ago
Need help finding out what 3x=y and x-2y = 10
sweet-ann [11.9K]

Answer:

x=-2, y=-6

Step-by-step explanation:

Simple substitution.

Since y is isolated in one of the equations already, you can plug it into the second equation.

x - 2(3x) = 10

x - 6x = 10

-5x = 10

x = -2

Sub. x = -2 into 3x = y:

3(-2) = y

y = -6

4 0
3 years ago
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