Factor:<br> a^2 +4a+5<br><br> Can Include imaginary numbers

Paul drove 225 miles to visit his parents. The graph below shows the distance traveled and the total time of the trip. Write and

ziro4ka [17]

50mph

Step-by-step explanation:

The image of the motion of Paul's derive is attached already.

From the line graph we can obtain a lot of information that will help us unravel the average speed of Paul within the given time frame.

What is average speed?

Average speed is the rate of change of total distance covered with time taken .

Average speed = $\frac{total distance }{time}$

To find the total distance covered;

Distance at time 1 = 75miles

Distance at time 4 = 225miles

Distance covered between 1 - 4 = 225 - 75 = 150miles

Time taken for the journey = 4 - 1 = 3hrs

Input the values in the equation;

Average speed = $\frac{150}{3}$ = 50mph

learn more:

Speed and motion brainly.com/question/10048445

#learnwithBrainly

5 0

3 years ago

Brenna saved 36% on a $15 pair of sunglasses. Choose the correct expression to find 36% of $15.

zhuklara [117]

Answer:

$5.40

Step-by-step explanation:

Take 15$ and multiply it by 36% or 0.36 and you get $5.40.

Hoped this helped, have a nice day!

4 0

2 years ago

Read 2 more answers

A company rents bicycles to customers. The company charges an initial fee

photoshop1234 [79]

The hourly rate is $3 a hour with a $2 initial fee.

5 0

2 years ago

32 POINTS

Nimfa-mama [501]

Answer:

c

Step-by-step explanation:

5 0

2 years ago

Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems

Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for $(x_{1},y_{1}) and (x_{2},y_{2})$

Use the distance formula to find the length = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point B (4,5) will be point 1 and point C (8,-3) will be point 2

Substitute

length = $\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\$

length = $\sqrt{80}$

length = 8.94

Use the distance formula to find the width = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width = $\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\$

width = $\sqrt{(-10 )^{2} + (11 )^{2}}\\$

width = $\sqrt{100 + 121}\\$

width = $\sqrt{221}$

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

7 0

2 years ago

Factor: a^2 +4a+5 Can Include imaginary numbers