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3 years ago

What is to 3v=v+6? I just in chance this is for homework.

Mathematics

1 answer:

hjlf3 years ago

8 0

3v=v+6

Subtract v from both sides

3v-v = v+6-v

2v= 6

Now divide both sides by 2

2v/2=6/2

v= 3

I hope that's help:0

Lets check if the answer is good

all you need to do is to replace v by 3

3v=v+6

3(3)=3+6

9=9

The answer is good

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As a company manager for the Quick Money Business there is a 0.40 probability that you will be promoted this year. There is a 0.

Maslowich

Answer:

Probability of getting raise when you get promoted = 0.625

Step-by-step explanation:

We have to find the probability of getting a raise. So,

Promotion = P, Raise = R

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Now we find the probability of getting a raise,

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3 years ago

Please answer this correctly as soon as possible

olya-2409 [2.1K]

Answer:

0, 4, 8

Step-by-step explanation:

For a number to be divisible by 8, the number formed the last 3 digits must be divisible by 8.

You have 7_4.

Try 704: 704/8 = 88

0 works

Now you can add multiples of 8 to 704:

704, 712, 720, 728, 736, 744, 752, 760, 768, 776, 784, 792

The only other numbers of the form 7_4 are 744 and 784.

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3 years ago

It has snowed 4 feet of snow. This is 60% of the snow that will fall. How much snow

Anvisha [2.4K]

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2 years ago

Read 2 more answers

The graph of an absolute value function opens down and has a vertex of (0, -3). The domain of the function is . The range of the

Firdavs [7]

Answer:

Domain: All real numbers

Range: $y\leq -3$

Step-by-step explanation:

The domain is the set of all x values. The quadratic equation continue to operate over all x-values in both directions. The domain is all real numbers.

The range is the set of all y-values. Here the quadratic begins at -3 and continues in a downward direction forever. Then range is $y\leq -3$

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3 years ago

Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc

Anna11 [10]

Answer:

The final velocity v is 21.74 m/s.

Step-by-step explanation:

Given:

$\textrm{initial velocity} = u = 9\ m/s\\\textrm{acceleration} = a = 7\ m/s^{2}\\\textrm{distance} = s = 28\ m$

To find:

$\textrm{final velocity} = v = ?$

Solution:

As we know the third equation of motion is represented as

$v^{2} = u^{2} + 2\times a\times s\\$

Substituting the values u, a and s in the above equation we get

$v^{2} = 9^{2} + 2\times 7\times 28\\ =81 + 392\\=473\\$

$v =\±\sqrt{473} \\v =\sqrt{473} \ \textrm{as acceleration is positive v is also positive}\\v = 21.74\ m/s$

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3 years ago