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aleksandrvk [35]
3 years ago
15

What is refraction of light​

Mathematics
1 answer:
USPshnik [31]3 years ago
8 0

Answer:

Refraction is what happens when light passes through some medium and changes it's direction because of it. For instance, when light travels through a lens light is bent as it goes from air to glass and back to air again. :)

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Diagram 1 shows a composite solid consisting of a cuboid and a right pyramid.
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44 the total volume of this composite solid is 896
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Name a street that is perpendicular to Hwy 64/40 . Can you help with all these questions
schepotkina [342]

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3 years ago
CAN YOU HELP ME PLEASEEEE ITS GEOMETRY!!! THANK YOUUU
SVEN [57.7K]

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117

Step-by-step explanation:

The angles line up~ P is the same as angel I.

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2 years ago
A rectangular room is 6.8 meters longer than it is wide, and perimeter is 29.6 meters. Find the dimensions of the room.
GuDViN [60]

Answer:

dimensions = 10.8  X 4

Step-by-step explanation:

Breadth/ width of room = x

Length of room =  6.8 + x

perimeter = 2 ( L + B )

29.6 = 2 ( 6.8 + x + x )

29.6/2 = 6.8 + 2x

14.8 - 6.8 = 2x

8 = 2x

8/2=x

4=x

Length of room =  6.8 + x = 6.8 + 4 = 10.8 m

Breadth/ width of room = x = 4m

8 0
3 years ago
Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137
Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em>78.70^\circ.

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle \triangle ABC with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles \angle A, \angle B, \angle C

As per Law of cosine:

cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}

Putting the values of a,b and c to find out angles \angle A, \angle B, \angle C.

cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ

cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ

cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ

<em>Camera 2nd has to cover the maximum angle</em>, i.e. 78.70^\circ.

6 0
3 years ago
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