Answer with Step-by-step explanation:
16 19 21 26 27 29 34 35 35 39 40 41 42 50 50 52 57 60 75 76 78 81 84
the data is already arranged in ascending order
Min=16
Max=84
The quartiles for the odd set of data is given by
where n is the number of elements
Here, n=23
Q1=6 th term
Q1=29
Q2=12 th term
Q2=41
Q3=18 th term
Q3=60
Hence, five-number summary for the given data is:
Min Q1 Q2 Q3 Max
16 29 41 60 84
Answer: x=2.4
Step-by-step explanation: I believe that you plug what y equals into the x value so both variable are x and you can solve for x
Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) =
= 0.25
P(X ≥ 15) =
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50