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mamaluj [8]
3 years ago
7

How many udders does a cow have

Chemistry
1 answer:
Zinaida [17]3 years ago
6 0
Nice question. A cow has 4 udders 
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What type of element is Hydrogen? Where do you see hydrogen present?
PSYCHO15rus [73]

/~\ The correct answer is:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

<em><u>Hydrogen is a chemical and is </u></em><em><u>found in the sun and most of the stars, </u></em><em><u>and the</u></em><em><u> planet Jupiter</u></em><em><u> is composed mostly of hydrogen. On Earth,</u></em><em><u> </u></em><em><u>hydrogen is found in the</u></em><em><u> greatest quantities as water.</u></em>

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8 0
3 years ago
Which of the following is not the same as 8,540 centigrams?
Dahasolnce [82]
8.54 Probably a little too late but, hey better late than never lol
8 0
3 years ago
Read 2 more answers
During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6 diffuses 0.4% faster than 238UF6. S
Kay [80]

<u>Answer:</u> The below calculations proves that the rate of diffusion of ^{235}UF_6 is 0.4 % faster than the rate of diffusion of ^{238}UF_6

<u>Explanation:</u>

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

We are given:

Molar mass of ^{235}UF_6=349.034348g/mol

Molar mass of ^{238}UF_6=352.041206g/mol

By taking their ratio, we get:

\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{M_{(^{238}UF_6)}}{M_{(^{235}UF_6)}}}

\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{352.041206}{349.034348}}\\\\\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\frac{1.00429816}{1}

From the above relation, it is clear that rate of effusion of ^{235}UF_6 is faster than ^{238}UF_6

Difference in the rate of both the gases, Rate_{(^{235}UF_6)}-Rate_{(^{238}UF_6)}=1.00429816-1=0.00429816

To calculate the percentage increase in the rate, we use the equation:

\%\text{ increase}=\frac{\Delta R}{Rate_{(^{235}UF_6)}}\times 100

Putting values in above equation, we get:

\%\text{ increase}=\frac{0.00429816}{1.00429816}\times 100\\\\\%\text{ increase}=0.4\%

The above calculations proves that the rate of diffusion of ^{235}UF_6 is 0.4 % faster than the rate of diffusion of ^{238}UF_6

3 0
3 years ago
The gas in an aerosol container is at a pressure of 3.50 atm at 24.0C. The caution on the container warns against storing it at
AVprozaik [17]

Answer:

4.34atm

Explanation:

The following data were obtained from the question:

P1 = 3.50 atm

T1 = 24°C = 24 +273 = 297K

T2 = 95°C = 368K

P2 =?

Using P1 /T1 = P2 /T2, we can obtain the new pressure as follows:

P1 /T1 = P2 /T2

3.5 / 297 = P2 / 368

Cross multiply to express in linear form:

297 x P2 = 3.5 x 368

Divide both side by the 297

P2 = (3.5 x 368) /297

P2 = 4.34atm

Therefore, the gas pressure in the container at 95°C will be 4.34atm

8 0
4 years ago
How many valence electrons does each of the following atoms have?
Zolol [24]
Which atoms?  ~~~~~~~~~~~~~~~~~~~~~~~~~`
6 0
4 years ago
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