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3 years ago

What is the molarity of a CaCl2 solution containing 150g of CaCl2 in 400 mL?

Chemistry

1 answer:

andre [41]3 years ago

3 0

Answer:

you have a 3.17molal solution: This is 3.17mol CaCl2 dissolved in 1 litre of water. Make this solution.

Molar mass CaCl2 = 110.9848 g/mol

3.17mol = 3.17*110.9848 = 351.822g

Total mass = 1000g H2O + 351.822g CaCl2 = 1,351.822g

Volume of this solution:

Volume = mass / density

Volume = 1,351.822/1.24

Volume = 1,090.2 mL

You have 3.17mol CaCl2 dissolved in 1,090.2 mL solution

Mol CaCl2 dissolved in 1000mL solution = 1000/1090.2*3.17 = 2.91 mol CaCl2

Molarity of CaCl2 solution = 2.91M

Explanation:

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Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of $MgCl_2$ (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of $MgCl_2$ (solute) = 3.37 g

First we have to calculate the mass of solute.

$\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2$

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$\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g$

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg$

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

$\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%$

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

$\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%$

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

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3 years ago

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