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viva [34]
3 years ago
10

The expression 36a+16b factored using the gcf is

Mathematics
2 answers:
Rzqust [24]3 years ago
7 0
36a+16b. The greatest common factor is 4
= 4(9a+4b)
zysi [14]3 years ago
7 0

Answer:

4(9a+4b)

Step-by-step explanation:

We have the expression 36a+16b, we can see that the greatest common factor (gcf) between 36 and 16 is 4.

The factors of 36 are : 1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 16 are: 1, 2, 4, 8, 16

Then,

36a+16b=\\4.(9a)+4.(4b)=\\=4(9a+4b)

The answer is 4(9a+4b)

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3 years ago
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nikitadnepr [17]

Answer:

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Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

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2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

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3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

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What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

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4 years ago
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Hello there,

"<span>RP" is a traversal line.
</span>
This would result that  it would be passing through "ST and PQ."

Hope this help's.

~Jurgen
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