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3 years ago

1. Rahul started his homework at 5.25 and ended his homework at 6:40. Find the elapsed time.

Mathematics

1 answer:

Darya [45]3 years ago

8 0

Answer:

1. 75 minutes

2. 5:50

Step-by-step explanation:

you have to add and subtract

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Seven less than three-fifths times a number is less than or equal to eighteen. Which inequality BEST represents this situation?

denis-greek [22]

$( \frac{3}{5} )*x - 7\leq 18$

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3 years ago

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PLS PLS PLS PLSSSSS HELPPPP

ioda

Answer: 14

Step-by-step explanation:

Okay so it asks in all, which means morning distance + afternoon distance

We got the afternoon distance so now we have to find the morning one

it says the afternoon distance (6), is 25% less than the morning distance.

Which means the afternoon distance is 0.75 of the morning distance.

so 0.75x = 6, x = 6/0.75 = 8

Then you add 8 to 6 to get 14

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3 years ago

A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

5 0

3 years ago

Mirele needs to buy fencing to completely surround her backyard pool. How much fencing should she buy? A pool has a length of 31

RoseWind [281]

Answer:

93.18 feet

Step-by-step explanation:

Given:

Length of backyard pool = 31.74 feet

Height of backyard pool = 14.85 feet

To find: Length of fencing bought by Mirele

Solution:

To find the length of fencing bought by Mirele, use the formula for the perimeter of a rectangular pool.

Length of fencing bought by Mirele = 2 ( length + height ) = 2 ( 31.74 + 14.85 ) = 2 ( 46.59 ) = 93.18 feet

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What is the estimate for 23 3/8

Bumek [7]

23 x 8 = 184

184 + 3 = 187 = 187/8

187 / 8 = 23 3/8

Answer: 187/8

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