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2 years ago

Given f(x) = -x + 6 write an equation for f(x + 3).

Mathematics

1 answer:

givi [52]2 years ago

6 0

Answer:

-fx +9f

(i think)

Step-by-step explanation:

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Which number line represents the solution to the inequality x - 3 > 2

Ivahew [28]

Answer: x > 5

Step-by-step explanation: To solve for x in this inequality, our goal is the same as it would be if this were an equation, to get x by itself on one side.

Since 3 is being subtracted from x, we add 3 to

both sides of the inequality to get x > 5.

When graphing x > 5, we have an open circle on 5 and the

open circle tells us that 5 is not part of our answer.

Then we draw an arrow going to the right to represent

all possible solutions to this inequality, any number greater than 5.

6 0

3 years ago

What is the mean absolute deviation (MAD) of the data set?

irakobra [83]

Answer:

2+6+8+12+12=40

40 divided by 5=8

6+2+0+4+4=16

16 divided by 5=3.2

MAD=3.2

Step-by-step explanation:

3 0

2 years ago

Logariths, please help

Valentin [98]

Answer:

{ - 2 , 8 }

Step-by-step explanation:

$log_{4}$ ( x² - 6x ) = 2

4² = ( x² - 6x )

x² - 6x - 16 = 0

- 6 = - 8 + 2

- 16 = - 8 * 2

( x - 8 )( x + 2 ) = 0 ⇒ $x_{1}$ = - 2 , $x_{2}$ = 8

{ - 2 , 8 }

3 0

2 years ago

Suppose that a function f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence

Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

$\lim_{x \to c} \frac{x^2-cx}{(x-c)}$

We can simplify it

$\lim_{x \to c} \frac{x(x-c)}{(x-c)}$

$=\lim_{x \to c} x$

$=c$

so, we can see that limit exist and it's value defined

case-2:

$\lim_{x \to c} \frac{1}{(x-c)}$

Left limit is

$\lim_{x \to c-} \frac{1}{(x-c)}$

$=-\infty$

Right Limit is

$\lim_{x \to c+} \frac{1}{(x-c)}$

$=+\infty$

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0

3 years ago

De (x - 5)2 = (5x - 3)2 = (x + y)2 =

zimovet [89]

Here is my answer, hope to help you

6 0

2 years ago