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3 years ago

Which expression is equal to

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

7 0

Answer: D
Hopefully this helps!! Mark me brainliest if it did!

Margaret [11]3 years ago

6 0

Answer:

Step-by-step explanation:

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Can someone help me with this?

Vladimir79 [104]

Answer:

poop

Step-by-step explanation:

poop

3 0

3 years ago

To win a particular lottery game, it is necessary to match numbers on 5 balls that are randomly picked from 65 balls numbered 1-

emmainna [20.7K]

Answer: $5.34*10^{-5}$

Step-by-step explanation:

given data:

number of balls = 65.

special black ball that is picked from 10 other balls = numbered 0-9.

Solution:

probability that a single lottery ticket will match 2 balls and the special black ball.

$= 65C2*9C1\\\\= 18720\\\\=\frac{1}{18720} \\\\= 5.34*10^{-5}$

5 0

3 years ago

Please help with these 3 questions

Sever21 [200]

Answer: x = 11

Step-by-step explanation:

2x+5 = 3x-6

2x-3x = -6-5

-x = -11

x = 11

Double-check:
11*2= 22 11*3=33

22+5 = 27 33-6= 27

4 0

2 years ago

Evaluate the following expression. -8 - (-10)^2. please please help I will give brainlist 1st who ansers

Alekssandra [29.7K]

Answer:

-108

Step-by-step explanation:

-8 - ( -10 )²

= -8 - 100

= -108

5 0

3 years ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago