Hello : <span>4x − 3y + 2z = 5 ... (P) </span><span>x + 6y + 7z = 3 ..... (Q) the perpendicular vector to the (P) is : v(4,-3,2) </span>the perpendicular vector to the (Q) is : l(1,6,7) v <span>⊥ l because : (4)(1)+(-3)(6)+(2)(7= =0 </span>so : (P) ⊥ (Q)