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3 years ago

Why is specific heat important

1 answer:

3 0

Hey!!

here is your answer >>>

Specific heat is the amount of heat required to raise the temperature of a unit substance!. The most common example!. The specific heat of water is 1 !. And, lot of plays and animals live under the water and if the specific heat of the water would be low, then the aquatic organisms would die, but the specific heat is high and it is hard for the sun to increase the temperature!.

Hope my answer helps!

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a certain car is capable of accelerating at a rate of 10.60m/s^2. how long does it take for this car to go from a speed of 55/mi

irina [24]

Use the equation:
v = u + at
because it has all the variables given and need to find. First you must make sure units are the same. Acceleration is given in m/s^2. Check to make sure this is correct before using the following solution. Convert acceleration from meters per second squared to miles per hour squared.

look up conversion meters to miles
1 mile = 1609.34 meters
10.60 m/s^2 * 1mile/1609.34m = 0.0069 mi/s^2
there are 3600 seconds in an hour, then there are 3600s*3600s in 1 hr^2
0.0069 mi/s^2 * 3600s*3600s/hr^2 = 85362 mi/hr^2

Then using: v = u +at
60 = 55 + 85362t
60 - 55 = 85362t
5 = 85362t
5/85362 = t
5.9 x 10^-5 hr = t
very small value in hours, multiply by 3600 to convert to seconds.

5.9 x 10^-5 hr * 3600s/hr = 0.21 seconds

7 0

3 years ago

A circuit is constructed with six resistors and two batteries as shown. The battery voltages are V1 = 18 V and V2 = 12 V. The po

kaheart [24]

The I3 will be 158 A.

<h3>How to find the current through the circuit?</h3>

The foundation of circuit analysis is Kirchhoff's circuit laws.
We have the fundamental instrument to begin studying circuits with the use of these principles and the equation for each individual component (resistor, capacitor, and inductor).
These rules aid in calculating the current flow in various network streams as well as the electrical resistance of a complicated network, or impedance in the case of AC.

To calculate I3 firstly, V4 has to be calculated,

$V_{4} =I_{4} R_{4}$

$V_{4} = V_{2} / R_{4} + R_{5} * R_{4}$

$V_{4} = 12 * 135 / 135+61$

$V_{4} = 8.26V$

For I3,

$I_{3} = R_{1} /(R1+R3 + (R1+R3)(R2+R6) * (V2 - V1 (R1+R2+R6/R1)$

$I3=(61)/((61)(50)+(61+50)(141+141)) (12 -18 (1+(141+141)/61)) = -.158 A$

Hence, the current through I3 will be 158 A.

To learn more about Kirchoff's laws refer to:

brainly.com/question/86531

#SPJ 10

7 0

2 years ago

4.0km at 25 west of south, then 2.0km at 15 north east

Aliun [14]

please, give the question properly.

3 0

3 years ago

What is intermolecular forces and how is it related to phases of matter

MakcuM [25]

Intermolecular forces are forces that keep molecules together. For example, the forces between two water molecules. The stronger the intermolecular forces are, the more "solid" is the matter going to be, meaning that the intermolecular forces are the strongest in solids and weakest in gases.
Make sure not to confuse intERmolecular forces (forces between *molecules*) and intRAmolecular forces (forces between *atoms* that make up a molecule).

6 0

3 years ago

A car initially at rest accelerates at 10m/s^2. The car’s speed after it has traveled 25 meters is most nearly... A.) 0.0m/s B.)

STALIN [3.7K]

The car traverses a distance $x$ after time $t$ according to

$x=\dfrac12at^2$

where $a$ is its acceleration, 10 m/s^2. The time it takes for the car to travel 25 m is

$25\,\mathrm m=\left(5\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=\sqrt 5\,\mathrm s$

5 is pretty close to 4, so we can approximate the square root of 5 by 2. Then the car's velocity $v$ after 2 s of travel is given by

$v=\left(10\dfrac{\rm m}{\mathrm s^2}\right)(2\,\mathrm s)\approx20\dfrac{\rm m}{\rm s}$

which makes C the most likely answer.

3 0

3 years ago